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Solution :

Line PQ<br>
`(y-2)=m(x-1)`<br>
If x=0 then y=2-m<br>
if y=0 then x=`1-2/m`<br>
Area of `/_OPQ=1/2(2-m)((m-2)/m)`<br>
after differentiate with respect to m<br>
`(deltaA)/(deltam)=delta/(deltam)(-1/2(m-2)^2/m)`<br>
putting`(deltaA)/(deltam)=0` and solving it we get<br>
`m^2=4`<br>
`m=pm2`
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